Solution)
Given,
I=0.48 kg-m^2
V=18.8 m/s
Distance, d=0.41 m
We know,
Rotational Kinetic Energy= ½Iω² = ½I(v/r)²
Rotational KE = ½ * 0.48kg·m² * (18.8m/s / 0.41m)²
= 504.61 J
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