Homework Answers
Answer a:)
Parental genotypes:
Dichaete flies = D++/+++
Parental dichaete flies have the above genotype because F1 generation has normal Dichaete with normal body and eye offspring. It is possible if parental dichaete is homozygous for body and eye color while heterozygous for dichaete.
Pure breed ebony rose flies = +er/+er
Parental cross:
Der/+++ x +er/+er
F1 progeny D++/+er
F1 progenies are Dichaete with normal body and eye color.
Answer b:)
To make the genetic map, find out the order of genes. Dichaete rose and Ebony offspring are the products of double crossover. Therefore, the ebony gene is present in between Dichaete and rose.
Therefore, the order is D E R.
Now calculate the map distance between the genes:
Between D and E:
Map distance % = (Progenies of single cross over + Double Crossover Progenies) / Total Progenies
Progenies of single cross over = Dichaete Ebony rose + Wild type
Progenies of single cross over = 45 + 62
Progenies of single cross over = 107
Double Crossover Progenies = 4 + 9
Double Crossover Progenies = 13
Map distance % = (107 + 13) /1000
Map distance % = 0.12
Map distance = 0.12 x 100
Map distance = 12 cM
Between E and R:
Map distance % = (Progenies of single cross over + Double Crossover Progenies) / Total Progenies
Progenies of single cross over = Dichaete Ebony + rose
Progenies of single cross over = 111 + 96
Progenies of single cross over = 207
Double Crossover Progenies = 4 + 9
Double Crossover Progenies = 13
Map distance % = (207 + 13) /1000
Map distance % = 0.22
Map distance = 0.22 x 100
Map distance = 22 cM
Therefore, the map should be like below:
D----------E-------------------R
Answer c:)
To calculate the interference, calculate the Coefficient of Coincidence by using the following formula:
Coefficient of Coincidence = (Actual DCO) / (Expected DCO)
Actual DCO = 13
The expected DCO products will follow the rule of independent assortment in the F2 generation. The expected ratio of the test cross is 1:1:1:1:1:1:1:1 ratio.
Expected DCO = 2/9 x Total offspring
Expected DCO = 2/9 x 1000
Expected DCO = 222
Coefficient of Coincidence = 13 / 222
Coefficient of Coincidence = 0.059
Interference = 1 – Coefficient of Coincidence
Interference = 1 – 0.059
Interference = 0.941 or
Interference = 0.941 x 100
Interference = 94.1%
Therefore, there is 94.1% of interference is present.
Add Answer to:
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