Question

Check my work Required information A capacitor is charged to an initial voltage Vo. The capacitor is then discharged by connecting its terminals through a resistor. The current l(7) through this resistor, determined by measuring the voltage AVR(0) = |(t) R with an oscilloscope, is shown in the graph. Part 1 of 2 10 points eBook Hint I (mA) Print References 0 10 40 50 20 30 1 (ms) If Vo = 9.00 V, find the total energy dissipated in the resistor. Dmj

Answer 1

V. = 9volts
and
1. = 100mA

current is given by

1(t) = 10e-t/

When

t = 1. 1 = 0.3681, = 0.368 x 100 = 36.8m A

Then

T 12.8ms

Now resistance is

R= vo 9 1. 100 10-3

T= RC = 12.8 x 10-3 = 90C C = 0.0128/90 = 1.42 x 10-4 = 1424 F

Total Energy dissipated by resistor will be energy stored by capacitor

Now,

E =-CV2 = 0.5 x 1.42 x 10-4 x 92 = 5.751 x 10J = 5.75mJ