a sulfuric acid solution containing 551.5
given
mass of solute H2SO4 = 551.5 g
we have molar mass of H2SO4 =98.079 g/mol
so number of moles of H2SO4 present = given mass/molar mass
= 551.5 g/98.079 g/mol
=5.623 mols***
volume of solution = 1L = 1000 ml
density of solution =1.33 g/cm^3
So mass of solution = volume *density = 1000 cm^3 * 1.33 g/cm^3 = 1330 g
mass of water = 1330 g- 551.5 g= 778.5 g
mass of water in Kg = 0.7785 Kg
molality = number of moles of H2SO4/mass of solvent in Kg = 5.623 mols*/0.7785 Kg
= 7.223 m
*******************
Thank you
a sulfuric acid solution containing 551.5 (a) A sulfuric acid solution containing 551.5g of H2SO4 per...
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