144Nd60 (Neodymium, element 60 with 60 protons and 144 nucleons) decays by alpha particle emission as...
144Nd60 (Neodymium, element 60 with 60
protons and 144 nucleons) decays by alpha particle emission as
follows: 144Nd60 --> 
+ 140Ce58 + 2e + an essentially massless
neutrino (Cerium has 58 protons and 140 nucleons). If the atomic
masses are: 144Nd60: 143.910082 amu, alpha
particle: 4.0015065 amu, 140Ce58: 139.905434
amu and the electrons have a rest mass of 5.48581*10-4
amu, how much energy is released in this decay process, in MeV?
Homework Answers
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144Nd60 (Neodymium, element 60 with 60
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