What is the value of each of the angles of a triangle whose sides are 148, 190 and 94 cm in length?
here,
sides , a = 1.48 m , b = 1.9 m , c = 0.94 m
let the angles be A , B and C
so,
cos(C) = (a^2 + b^2 - c^2) /( 2 * a * b)
cos(C) = ( 1.48^2 + 1.9^2 - 0.94^2) / ( 2 * 1.48 * 1.9)
C = 29.04 degree
and
cos(B) = ( a^2 + c^2 - b^2)/( 2 * a * c)
cos(B) = ( 1.48^2 + 0.94^2 - 1.9^2) / ( 2 * 1.48 * 0.94)
B = 101.11 degree
and
A + B + C = 180 degree
A + 29.04 + 101.11 = 180
A = 49.85 degree
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