Question

Consider that an 10-sided die, numbered 1-10, is rolled. Find the probability that the roll results in an odd number or a number greater than nine? a) 0.70 b) 0.80 Oc) 0.60 d) 0.85 O e) 0.90

Answer 1

Answer:

c) 0.60

Explanation:

The die is 10 sided, numbered 1-10.Hence the probability of result of each number from 1-10 is same. And it will be 1 / n = 1/10 = 0.10

Now The probability that the roll result in an odd number or number greter than 9 . There are 5 odd numbers ( i.e. 1, 3 , 5, 7, 9) , and 1 number greater than 9 ( i.e. 10)

Let X be the number on die

propbability is given as :

P( number is odd or greater than 9 ) = P ( number is odd ) + P( number is greater than 9 )

= { P(  X = 1 ) + P(  X = 3 ) + P(  X = 5 ) + P(  X = 7 ) + P(  X = 9 ) } + P ( X = 10 )

= { 0.10 + 0.10 + 0.10 + 0.10 + 0.10 } + 0.10

= 0.60

The probability that the roll result in an odd number or number greter than 9 is 0.60