Question

con 308 Problem 10.28 Question Help Based on a careful work study in the Hofstetter Corp., the results shown in the following table have been observed: 302 S Element Prepare daily reports Photocopy results Label and package reports Distribute reports Performance Rating 125% 115% 85% 90 % 1 35 11 Observation (minutes per cycle) 2 3 39 34 41 1 0 37* * Photocopying machine broken; included as delay in the allowance factor * Power outage, included as delay in the allowance factor The allowance factor for this type of work is given to be 18%. (Round all intermediate calculations to two decimal places before proceeding with further calculations.) a) The normal time for the prepare daily reports" operation = minutes (round your response to two decimal places). Enter your answer in the answer box and then click Check Answer. parts O remaining Clear All Check Answer

a) The normal time for the "prepare daily reports" operation = _________ minutes (round your response to two decimal places).

The normal time for the "photocopy results" operation = __________ minutes (round your response to two decimal places).

The normal time for the "label and package reports" operation = _________ minutes (round your response to two decimal places).

The normal time for the "distribute reports" operation = _________ minutes (round your response to two decimal places).

The normal time for the overall process = _________ minutes (round your response to two decimal places).

b) The standard time for this process = _______ minutes (round your response to two decimal places).

c) The number of observations that are required for a 99 % confidence level within 55 % accuracy = _____ (round your response to the immediate higher whole number).

Answer 1

a)

Average Time = Average of observations

Normal time = Average Time * performance rating

Example:

For Prepare Daily reports,

D | Ε F I 39 Α 1 Rating 125% 110% 95% 90% 10 G H 5 Avg. Time Normal Time 40 37.80 47.25 12.25 13.48 5 4.20 3.99 17.50 15.75 80.47 35 11 4 15 13 4 18 21 16

Average Time = Average(35,39,34,41,40) = 37.8 minutes

Normal Time = 37.8*125% = 47.25 minutes

Normal time for over a process = sum of all normal times = 80.47 minutes

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