Question

Police response time to an emergency call is the difference between the time the call is first received by the dispatcher and the time a patrol radios that it has arrived at the scene. Over a long period of time, it has been determined that the police response time has a normal distribut with a mean of 10.4 minutes and a standard deviation of 1.7 minutes. For a randomly received emergency call, find the following probabilities (For each answer, enter a number, Round your answers to four decimal places.) (a) the response time is between 7 and 12 minutes (b) the response time is less than 7 minutes (c) the response time is more than 12 minutes Need Help? Read It Talk to a Tutor 17. -/5.26 POINTS BBBASICSTATSACC 7.5.006.MI. MY NOTES ASK YOUR TEACHER Suppose x has a distribution with a mean of 80 and a standard deviation of 51. Random samples of size n - 36 are drawn. (a) Describe the x distribution Type here to search A de PME

Answer 1

of Given data nomal distoibution with .. mean M= 1004 Standard deviation 6 = 17 1. @ the gesponse time is between 7 and 18 min B : cele vee the formula fall ä Standaard Z-value : P[72xx125= ?[3:7 2 ="] vi 3.4 Z = P[-85 73.094] = P[720.943 –P[22-2] from Standard halmal distribution 7 sable the Ascar lebt of the cave at Z=094 is p = 0.88 64 Zana 8 Pa 0.9275 P[<x<1a) = 0-8964 -9995 20.5989 T: P[72X<19] = 0-5989]

- 7 min; The response time less than P[x<+]= P[727-41] SEGG the cuore att = p[ze 3:43 - Pſz + -a] from Standard fuble the area. left to 7=-_18 0-2275 1. P[x<+] = 0.0345 AL . © The gesponse time note tham la min: p[x>19] = 1- P[x<la] - 5-P[744] 21 - p[7 20-943 3 1 - 0.8264 in 0.1736 1 : P[x>14] 2011736

④ Given neam = 80 Standard deviation 51 :) Lample size 65 36 B @ The sampling dissibution of the means caill be approximately normally distributed