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PLEASE SHOW ALL WORK AND STEPS

(5) A wire loop carries a current i traveling in the clockwise direction. The loop is fixed in such Ph a way that it can rotate about the axis (dashed line) shown in the figure (a) In what direction will the magnetic field need to point for the loop to rotate counter clockwise, when viewed from above, about its axis? Explain the reasoning behind your answer (A) Up Down (B) (C) Left (D) Right (E) Into the Page (F) Out of the Page We are interested in finding the total force exerted on half of the loop. The problem is the angle between the current direction ila, and the magnetic field, B, is different everywhere on the loop (see figure), so we cannot easily calculate F iL x B (b) To tackle this, lets divide the loop up into an infinite number of little current segments idL, each creating a infinitesimal force, dF idL x B. Set up an integral to calculate the force on half of the loop. dD is a little arc-length. Write an expression for dl in terms of r, the radius of the loop, and do, the angle subtended by the arc-length (recall, s- re) (c) The radius of the loop is 0,012 m, the current in the co is 0.72 A, and the magnetic field has a strength of 0.36 T, Calculate the magnitude of the force on half of the loop. You do not need to provide an assessment of your answer

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kth whan vt wund fan, 욧tp 옹.tu kor alane de idしメ匡 2977 m

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