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Question 13 (1 point) ✓ Saved (Theory problem) On its own, a tow-truck has a maximum acceleration of 5.20 m/s2. What would be
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Answer #1

F_{max}=ma_{max} ----(1)

F_{max}=(2m+m)a'_{max}----(2)

Dividing (1) by (2),

1=\frac{a_{max}}{3a'_{max}}

a'_{max}=\frac{a_{max}}{3}=\frac{5.2}{3}=1.73\ m/s^{2}

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