Question

Open Response Questions Wednesday Homework Problem 12.11 A convex lens has a focal length of magnitude f = 3cm. An object is placed 8cm from the lens. The dark lines on the grid below each represent 1cm. (a) Draw the ray diagram and locate the image. Label the location of the primary and secondary focal points. (b)Indicate the positive direction on the optical axis. Mark important locations on the optical axis. (c)From your ray diagram, what is the magnification and image location. Make sure to report both with the correct signs. (d)Describe the image based on your ray diagram. (e) Compute the image location using the thin lens equation. (f) Compute the magnification. (g)Describe the image based on your computation. Tell why your calculation supports your description of the image. convex lens optical coordinate axis

Answer 1

Scale x-axis, 1 unit = 1cm. Yanis, I unit 1cm, ho 3cm 7 2F chi=-1.8cm. U= 8cm V=4.8cm F-primary focal point , F- secondary focal point of=+3 cm. (c) Location of the image, v= +4.8cm. Height of the object = 3 cm. Height of image = - 1.8cm .: Magnification = -1.8 -0.6 2 (d) Image is real and inverted, Smaller than object. C at > 15 +=> V- UF U+. -8x 3 Va 2 -24 4.8 cm 7.8 cm - 8+3

) Magnification, m = 48-06 (9) Since lul> 12+) and lens is Conver, the image is regl. Sign of Magnilication is negative, So image is invented Pm1 <1so the image is smaller than object.