Question

An Atwood's machine consists of masses m₁ and m₂, and a pulley of negligible mass and friction. Starting from rest, the speed of the two masses is 4.10 m/s at the end of 3.07 s. At that time, the kinetic energy of the system is 90.0 J and each mass has moved a distance of 6.30 m. Determine the lighter mass. Determine the heavier mass.

Answer 1

my solution- Apply conservation of Energy Emeche constent a k tlug intral. kao start from rest) a uso (measure h from starting positions) Final kta Ž (mitm) v2=90.0] Both blocks moving at some speed) afa migh-magh (Block 1 goes up, block a gones down) Emech = or kft ef K8= 890.09 -up 2x290) (mitm2) v2 290] =) mitmz - (4.10m/s) 2 43tokeo GoJ ahamiah =90] => marmar qisim/s2 x (6:36) mitm₂ = 10.71 kg - o m₂-ma= 1.46 kg - Adding both equation + m₂ + marfon = 10.71 +1146 2mza 12.17kg i mar 61083 kg heavier mass i mic 4.62 kg to lighter mass