A simple Atwood's machine uses two masses, m1 and m2. Starting from rest, the speed of...

Question

Question

A simple Atwoods machine uses two masses, m1 and m2. Starting from rest, the speed of the two masses is 10.0 m/s at the end

Answer 1

Answer #1

Final kinetic energy, K_f = 1/2 * (m1 + m2) * v²

Final potential energy, P_f ( assuming m1 moves up and m2 moves down) = m1*g*h - m2*g*h

We know that total mechanical energy is conserved

so,

K_f = 90 = - P_f

1/2 * (m1 + m2) * v² = 90

m1 + m2 = 1.8 ------------- (1)

m2*g*h - m1*g*h = 90

m2 - m1 = 90 / 9.8*40

m2 - m1 = 0.2296 Kg --------- (2)

solving (1) and (2), we have

m1 = 1.0148 Kg

m2 = 0.7852 Kg

Answer 2

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