Question

As shown in the figure below, two masses m1 = 4.80 kg and m2 which has a mass 80.0% that of my, are attached to a cord of negligible mass which passes over a frictionless pulley also of negligible mass. If m1 and m2 start from rest, after they have each traveled a distance h = 1.10 m, use energy content to determine the following. m M (a) the speed (in m/s) v of the masses m/s (b) the magnitude (in N) of the tension T in the cord N

Answer 1

T T mi = 4.8 kg mi mig = 4.8 x 80 m24 8 x 3o Long 14 ng. 3.84 mag g = 9.8 m/s2 tet, the masses will acelerate by 'f m/s2 Equation of motion of mass mi, mig- T = mif Equation of motion of T- m₂ g = m₂f T= m₂ g + m2f mig-m₂ g - mafamif (m, - m2) g = (mit me ) f fa mats m2 m - m2 m, + m2 g 1.08 m/32 a) Lel, velocity will be mis when afh ſafh (1) (g+f) = 41.78 N 2 uz u touches ground u²+ 2f hinzo m/s = 1.544 m/s.