Question

You have two equal masses m₁ and m₂ and a spring with a spring constant k. The mass m₁ is connected to the spring and placed on a frictionless horizontal surface at the relaxed position of the spring. You then hang mass m₂,  connected to mass m₁ by a massless cord, over a pulley at the edge of the horizontal surface. When the entire system comes to rest in the equilibrium position, the spring is stretched an amount d₁ as shown in figure (a). You are given the following information.

The mass m₁ = m₂ = 0.340 kg.

The spring constant k = 150 N/m.

(a) Determine the amount the spring is stretched (d₁) when m₂ is attached to m₁.

d₁ = (No Response) m

You now pull the mass m₂ down a distance d₂ = 8 cm and release it from rest, as shown in figure (b). Determine the following as the two masses travel the distance d₂ back to their equilibrium positions. (The masses will overshoot the equilibrium position, but we are focusing our attention on them only as they travel the distance d₂.)

(b) Determine the work done on the system (m₁, m₂, and the massless connecting cord) by the spring.

W_s = (No Response) J

(c) Determine the work done on the system by the force of gravity.

W_g = (No Response) J

(d) Determine the work done on the system by the normal force.

W_N = (No Response) J

(e) Determine the net work done on the system.

W_net = (No Response) J

(f) Determine the work done on m₁ by the tension in the cord.

W_T1 = (No Response) J

(g) Determine the work done on m₂ by the tension in the cord.

W_T2 = (No Response) J

Answer 1

Cuiven dater, miam2 = 0.340 kg K = 150 N/m. we know that, T= M29 ₃0 using equilibarum of force along the holimontal direction T= Fs M2 g = kdi t utela nal of (6.340) (9.8) = 150 (di) Ich -0.02227 by work done, ws, įk (@2t0,$_0,3) 4X150 (0.08 +0.0222)?-(0.02227) = 0.783-0.000492 fus -0.7825) Er work done by the foce of gravity is, wg = mg da 260.340)*(91890.08) Log = 0.2665

d, we know, Angle between normal force WN= Nd2c080 and dienacement = 90 = N d2X COS 900 (-2.008900-0) Wp =0