Question

Q3[2 marks]: Assume that you're the receiver and that the 4B/5B block coding is used. You're given all the mapping between 4 bits to Sbits. You received the following stream of bits: 0101010010101110001111011 EBBA alla CE TIDI What is the original data transmitted by the sender? Answer: Q4[1 mark] : If the bandwidth of a signal is 12 kHz, and the mid-point is at 29 KHz. What are the lowest and highest frequencies? Lowest frequency:.. Highest frequency:

Answer 1

Answer of Q3.

Image is blur so i can't understand

Original bits-01001000101101011101

Answer of Q4.

Given:-BW=12KHz , mid point=29KHz

So,

Lower Frequency = mid point - BW/2

=29 - 12/2

= 29 - 6

=23KHz

Higher Frequency=mid point + BW/2

=29 + 12/2

= 29 + 6

= 35KHz