Homework Answers
partial molar volume of MgSO4 in a mixture is the change in volume per mole of MgSO4 is added to the mixture.
V(cm3)=1001.21+34.96(b-0.070)^2
b=molality=0.050 mol/kg
total volume=V(cm3)= 1001.21+34.96(0.050-0.070)^2=1001.224 cm3
partial molar Volume of water = 1001.21(solvent)
So partial molar volume of MgSO4=1001.224 cm3-1001.21 cm3=0.014 cm3 (salt)
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