Question

Description: 25mL of a 0.09M CUSO4 solution is measured in a graduated cylinder and poured into a small beaker. A 0.27g sample of Na3PO, is measured in a weight boat and added to 25mL of distilled water in a beaker; the solution is swirled until all of the Na3PO4 has dissolved. The two solutions are slowly combined in a 100mL beaker and swirled to help complete the reaction, which forms a solid product; the beaker is set aside for 10 minutes. A dry piece of filter paper is massed at 1.2g; this filter paper and a Buchner funnel setup are used to filter the solid product. The filter paper now containing the solid product is set aside to dry; after drying, the filter paper containing the solid product is massed at 1.39g. 3. If 0.27g of Na3PO4 is used in the reaction, which reactant is the limiting reactant? Show your work.

Answer 1

Answer - Concentration of cuson = 0.09M 0.09 mal present in 12 salution' M 0121 1000 concentration of Na, Pou tcalulate) ul = 0. 27 g Maleler mass - Naz Pou = 3 Na +P+40 Valone - 25 me = 69 +31 + 64 = 164 gr malarity - w x 1000 - 0127 x 1000 = 0,065M 0.065 males of Na₂ pon present in 12 of satulion According to chemical Reaction 3 cusou + g Na₃PO4 - cug (POM), do + 3 Na₂SO4 3 males 2 males According to Equection 0.09 males 0.065 mas & ainen in quation wih 2 3 3 males of caso combine with = 2 mals of Na PO, 1 male of cuson combine with a % mas of Nepon 0.09 mas of cuson combine with a 2x0:09 mabot Nespon - 0106 males In this Reaction only 0.06 Nazpou is required ut. mals of we have 0.065 mals nazpon is Excess Reactant that is why (Cason is Umiting Reagent)