Question about ELECTRON CONFIGURATION. My professor said that the electronic configuration for Sc+ is [Ar]3d2. Why is it not [Ar]4s13d1?
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Question about ELECTRON CONFIGURATION. My professor said that the electronic configuration for Sc+ is [Ar]3d2. Why...
Which of the following is correct condensed electronic configuration for ground state V3+ion? Select one: a. [Ar], 4s0, 3d2 b. [Ar], 4s2, 3d0 c. [Kr], 4s0, 3d2 d. [Ne], 4s0, 3d2
The electron configuration for the cation of zinc is Question 16 options: [Ar]4s23d104p6 [Ar]4s23d10 [Ar]4s23d8 [Ar]3d10 [Ar]4s23d104p2
Why is electron configuration for V [Ar]4s^2 3d^3 instead of [Ar]4s^2 4d^3 Is it not in the 4th row??? Thanks.
Attempt 2 ion 22 of 29 > A pictorial representation of an electronic configuration is shown. T TL T 1s 2s 2p Give the full electron configuration. Do not use the noble gas abbreviation. electron configuration: Name the element, assuming that the configuration describes a neutral atom. element name: Question Source: MRG-General Chemistry| Publisher University Sc help contact us terms of use privacy policy about us careers MacBook Air
What is the electron configuration for the Fe3+ ion? Please explain why a.) [Ne]3s23p10 b.) [Ar]4s13d6 c.)[Ar]4s03d7 d.) [Ar]4s23d9 e.)[Ar]4s03d5
Give the chemical symbol for the element with the ground-state electron configuration [Ar]4s23d'. symbol: Sc Determine the quantum numbers n and 1 and select all possible values for me for each subshell of the element. 4s n= 45 l = The possible values of me for the 4s subshell are O-3, -2, -1,0, +1, +2, +3 0 -2,-1,0, +1, +2 0 -1,0, +1 Oo 3d n= 3d t = The possible values of me for the 3d subshell are O-2,...
Identify the correct condensed electronic configuration for the Mn ion. A) [Ar]4s23d B) [Ar] C) [Ar] 4s23d2 D) [Ar]3d E) [Ar] 4s24d5
electron configuration for scandium O ELECTRONIC STRUCTURE Drawing a box diagram of the electron configuration of an atom Draw the electron configuration for a neutral atom of scandium. energy 3p Click to change la
< Question 8 of 11 > Complete the electron configuration for Br. [Ar] BI V x2 x² SPECIAL GREEK ALPHABET
Question 22 5 pts The electronic configuration for boron is 1s22s22p1, and the electronic configuration for aluminum is 1s2 2s22p6 352 3p1. It requires 8.298 eV to remove the outermost electron (21) from boron. What can you say about the energy required to remove the outermost electron from aluminum (3p1)? Since each is the outermost electron around the atom, the energy required will be equal to 8.298 ev. Since each electron is in ap orbital, the energy required will be...