Question

Consider the combination of resistors shown in the figure below. 12.0Ω 4.00 Ω | 5.00 Ω - - 6.00 Ω 8.00 Ω (a) Find the equivalent resistance between point a and b. 11.7 (b) If a voltage of 26.9 V is applied between points a and b, find the current in each resistor. 2.3 12 Ω Your response differs from the correct answer by more than 100%. A Ο 6 Ω 5Ω 4 Ω 8 Ω

Answer 1

Here, for the net resistance

Rnet = 12 * 6/(12 + 6) + 5 + 4 * 8/(8 + 4)

Rnet = 11.7 Ohm

b) Using current divider rule

for the current in 12 Ohm

current in 12 Ohm = (26.9/11.7) * 6/(6 + 12)

current in 12 Ohm = 0.77 A

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current in 6 Ohm = (26.9/11.7) - 0.77

current in 6 Ohm = 1.53 A
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for the current in 5 Ohm

current in 5 Ohm = 26.9/11.7

current in 5 Ohm = 2.3 A

the current in 5 Ohm is 2.3 A

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Now, for the current in 4 Ohm

current in 4 Ohm = 2.3 * 8/(4 + 8)

current in 4 Ohm = 1.53 A

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for the current in 8 Ohm

current in 8 Ohm = 2.3 * 4/(4 + 8)

current in 8 Ohm = 0.77 A