Question

Calculate the number of moles in: 

a 18 g of methane, CH₄ 

b 236.0 g of nitric oxide, NO 

c 404.0 g of chlorine dioxide, CIO₂ 

d 892 g of glycerin, C₃H₈O₃ 

Answer 1

SOLUTION :

a.

Molar mass of CH4 = 12 + 4 = 16 g

So, number of moles in 18 g of CH4 = 18/16 = 1.125 moles (ANSWER)

b. 

Molar mass of NO = 14 + 16 = 30 g

So, number of moles in 236 g of NO = 236/30 = 7.87 moles (ANSWER)

c. 

Molar mass of ClO2  = 35 + 32 = 67 g

So, number of moles in 404 g of ClO2  = 404/67 = 6.03 moles (ANSWER)

d. 

Molar mass of Glycerine C3 H8 O3 = 36 + 8 + 48 = 92 g

So, number of moles in 892 g of C3 H8 O3 = 892/92 = 9.70 moles (ANSWER)

Answer 2

General formula: Number of moles = mass in grams мьих мию 68 | mog Сөз мав аль - 1 Со таа м * 2 - нисэх - 1 11 мм ON ) (c) mb o clo, = 40. о = S. 439 тод 1mog (1) molu o С, MgO2 = 342 X – Ч. 646 и o4