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Determine the support reactions and draw the shear and bending moment diagrams for the structure shown in Figure 1 by using tsolution step by step please

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method of consistent deformation I flexibility method 1 unit load method. X, khm X2kn/m sticiler am 4m El=constant X = 57knmmoment equation due to even load AB= 36363€ - 606xxr – 10851x (otos) Moc = 57 km (otoy) (otoy) McD = 57 km load at c. um um Mapply unit lood at D Em =0 MA=Ix8 MA= 8 (mal moment egh due to unit load at D (otoo) MAB = -8 MBC = x-8 (otoy) McD = x-4 (640egn. + 01 T + (-2)-5. I + * (-) (1520 – 106–1959 L-26-28 J+40-703) 65+ (435-0, 3+ 4% 52.] >> MM(924 19 (0* + 4318 (6) +57 (9229080(+ 204( 3 + 86858(0) + 57412_456() + $7(4)2 – 228(4) + Robu () + 3+120(4) – 16(42+ 4 +1644- ( 4-B اتها + Rc4 245.33=0 172M = 0 MA - MAY6 HRAY6 +4,6२४५ +57 =606X6Y 3 MA + 363696 - 213,२५४6 + ५.०२५५-57 = 10908 =-9163, 56 km s89148 छापा 14.62 208,6Bending moment diagram MA= -9163.56 knm MAB = -9163.56 +36367-60672 atx=6 m₂ = 1744,45 knm column Mer 1744.45- 213.24 (2) atx

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solution step by step please Determine the support reactions and draw the shear and bending moment...
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