Two charges are a distance d apart. By what factor will the force between the charges change if the separation between them is quadrupled?
Select one:
a. 8
b. 4
c. 1/16
d. 1/4
SOLUTION :
F is inversely proportional to squared distance.
=> F = k / d^2
So,
F1 = k / (d1)^2
F2 = k / (d2)^2
=> F2/F1 = (d1)^2 / (d2)^2 = 1 / [ (d2 / d1)^2 ] = 1 / 4^2 = 1 / 16
Hence, force between charges will be 1 / 16 times the initial force if distance is quadrupled : Option c (ANSWER).
Answer
1/ 16
as Force
, F1 = k q1 q2 / r^2
F2 = kq1 q2 / (4r)^2
F2 /F1 = 1/ 16
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