If a 5.5 m string is fixed at both ends, what is the fundamental resonance frequency (lowest frequency) of the string? Use 33 m/s for the speed of a wave in the string.
A string which is fixed at both ends will exhibit strong vibrational response only at the resonance frequncies
f = nv/2*L
f = 1*33/2*5.5
f = 3 Hz
If a 5.5 m string is fixed at both ends, what is the fundamental resonance frequency...
A string fixed at both ends has successive resonances with wavelengths of 0.55 m for the nth harmonic and 0.53 m for the (n + 1)th harmonic. (a) What are the following values? nth harmonic (n + 1)th harmonic (b) What is the length of the string? m Use the fact that the resonance frequencies are multiples of the fundamental frequency and are expressible in terms of the speed of the waves and their wavelengths to find the harmonic numbers....
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