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(16 pts) A mass m is attached to a spring which is held stretched a distance x by a force F, and then released. The spring co
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Answer #1

using hooke's law

F = kx

k = F/x

using conservation of energy

spring energy = fricitonal energy loss

0.5 k x^2 = u m g x

0.5 F/x * x^2 = u mg x

0.5 F = u mg

u = F / (2 mg)

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Comment in case any doubt, will reply for sure.. Goodluck

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