You are given metal stripes of Zn, Cu, Cd, Fe, Ni, Mg and their respective salt solutions Zn(NO3)2, Cu(NO3)2, Cd(NO3)2 , Fe(NO3)2 , Ni(NO3)2 , and Mg(NO3)2. Build 6 different electrochemical cells using the given materials and calculate the standard cell potential using Table 19.1, and write the cell notations for each of your electrochemical cell on the given space in the worksheet. One of the electrochemical cells must have the largest standard cell potential E°cell using the given materials.
1. Copper/Zinc Electrochemical
Cell Anode half-reaction:
Cathode half-reaction:
Cell Notation:
Eo value of this cell: _________________________
Which metal strip would get larger? _________________________
Which metal strip would get smaller _________________________
2. ___________________________________
Cell Anode half-reaction:
Cathode half-reaction:
Cell Notation:
Eo value of this cell: _________________________
Which metal strip would get larger? _________________________
Which metal strip would get smaller _________________________
You are given metal stripes of Zn, Cu, Cd, Fe, Ni, Mg and their respective salt...
An electrochemical cell uses Ni/Ni+2 and Cd/cd+2. a) Write the half reactions that will be spontaneous for this cell. Oxidation- Reduction- b) Which metal is the anode and which is the cathode? anode cathode c) Calculate the emf (Ecell) for this cell. Eceu =
Galvanic Measured Cell Equation for Anode Equation for Cathode Ecell Anode Reaction Cathode Reaction Cu-Zn @jcu-Mg M010 LL Sof Mane t Mu ?. (imus -ur.- 3) Cu-Fe Zn-M 5) Fe-Mg ?) Zn-Fe -A Write balanced equations for the six cell reactions 2 + Compare the sum of the Zn-Mg and Cu-Zn cell potentials with the Cu-Mg cell potential. Explain your result. Compare the sum of the Zn-Fe and Zn-Mg cell potentials with the Fe-Mg cell potential. Explain your result.
Half-cell Potentials: Half Reaction: E value +0.80 V Agt + e → Ag Fe3+ + € → Fe2+ +0.77 v +0.34 V -0.13 V Cu2+ +2e → Cu Pb2+ + 2e - → Ib Ni2+ + 2e → Ni Cd2+ +2e → Cd -0.25 V -0.40 V Fe2+ + 2e → Fe -0.44 V Zn2+ + 2e → Zn -0.76 V Al3+ +3e → AI - 1.66 V Consider an electrochemical cell constructed from the following half cells, linked by...
data collected Cu(NO3)2 | Zn(NO3)2 = 0.999 V Pb | 1.0 M Pb(NO3)2 || 1.0 M Zn(NO3)2 | Zn = 0.396 V PART B: REDUCTION POTENTIALS 1. Report the measured cell potential for each galvanic cell and state which electrode corresponds to the cathode and which to the anode. 2. Given E = -0.76 V for the Zn/Zn half-cell, and your measured Ecell, calculate the reduction potential at the Cu and Pb electrodes and write the redox half- 6 reactions...
*redox reactions in electeochemical cells* c) Fe/0.1 M FeSO4//0.1 M CuSO4/Cu I soaked a porous cup in tap water for a few minutes and then i let it stand in a 100 ml beaker containing 10ml of 0.1 M FeSO4. I added enough 0.1M CuSO4 to the cup until the two liquid levels were the same height. I inserted a zinc strip into the 0.1 M FeSO4 and a shiny copper strip into the 0.1 M CuSO4. I connected the...
Consider the activity series: ….. Mg > Al > Fe > Zn > H > Cu > Ag > Au …… Which of the statements will be true? i. in a voltaic cell Ag/Fe, element Ag will serve as anode and Fe will be cathode ii. Al will oxidize Cu, Ag, Au iii. Fe will reduce H, Cu and Ag iv. Cu will oxidize Al and Mg v. H is a stronger oxidizing agent than Cu, Ag A. i and...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) (a) Ca(II) and Sc(III) Cathode: . Ca(II) Sc(III) Anode: Ca(II) Sc(III) Ecell = 0.0591 x V (b) Pb(II) and In(III) Cathode: . Pb(II) In(III) Anode: Pb(II) In(III) Ecell - (c) Ni(II) and Zr(IV) Cathode: NI(II) Zr(IV) Anode: Ni(II) Zr(IV) Ecell - V Supporting Materials Periodic Table Supplemental...
Consider a voltaic (galvanic) cell with the following metal electrodes. Identify which metal is the cathode and which is the anode, and calculate the cell potential. (Use the table of Standard Electrode Potentials.) (a) Cd(II) and Sc(III) Cathode: Cd(II) Sc(III) Anode: Cd(II) Sc(III) Ecell 42 (b) Pb(II) and In(III) Cathode: Pb(II) In(III) Anode: Pb(II) In(III) Ecell - (c) Ni(II) and Zr(IV) Cathode: Ni(II) Zr(IV) Anode: Ni(II) Zr(IV) Ecell- Supporting Materials We were unable to transcribe this imageAGº and Eº can...
Need help with questions 1-5 D Determine whether each redox reaction occurs spontane- ously in the forward direction. (a) Ca2+(aq) + Zn(s)-Ca(s) + Zr"(al) (b) 2 Ag+(aq) + Ni(s)--2 Ag(s) + N产(aq) (c) Fe(s) +Mn2 (aą)- Fe (aą)Mn(s) (d) 2 Al(s) + 3 Pb2+(aq) → 2 AP"(aq) + 3 Pb(s) Suppose you wanted to cause Pb ions to come out of solu- tion as solid Pb. What metal could you use to accomplish this? Make a sketch of an electrochemical...
19 20 Question 16 Half-cell Potentials: Half Reaction: E' value + 0.80 V +0.77 V Agte → AS Fe3+ + + Fe2+ Cu2+ 2e → Cu Pb2+ + 2e → Pb +0.34 V -0.13 V Ni2+ + 2e → NI -0.25 V - 0.40 V Cd2+ +2e → ca Fe2+ + 2e → Fe Zn2+ + 2e → Zn -0.44 V - 0.76 V A13+ +3 → AI - 1.66 V Consider an electrochemical cell constructed from the following half...