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7. Mens heights are normally distributed with mean 69.5 in and a standard deviation of 2.4 in. Find the heights that separat

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- السل . Here we are given that xww (6965,2-4) P QX <r) - 0025 = P(x- 69.59 <1-69.5) = 0.025 O - plzLn- 69.5 = 0.025 94 - o 1| (8) P(x2): 1- P( 12列 > 1 - P(2 ) * 0.0369 (1) plexCJ-Plears = (6) =63-3) = p(-)-12 ) - 0-9267 Scanned with CamScanner4 P ( x cm) 0.25 PL 84 PLX - 69.5 n-695 - -025 24 ) = P2< 1.1670). 025 = 20-25 n-69.5--0-67 29.4 na 67. 8812 CScanned with Ca

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