Question

3. (21 pts) Compute the area of the region enclosed by the curves y = -2° + 5 and y = - 9x + 20.

Answer 1

fl= y = -x² +52 and g(0) = y=x2-gar 420 (upper function - action)-llower loan functionare ty=-22h (upper function) 51 2 y= re.9x420 - Clower function) find intersection points an Equate both equation a -ae2 +52 = 22-ga t20 2762-1422 +20=0 (276? -10%) - 97 +20 =0 2012-57-4(3-5)=0 (27-4) (22-5) =0 28e-4 = 0 and x-570 2x =4 and Tae =5 1 X=27 NOW, A = pas le tion - (live tom) dose = (-22+58) – (*2-926 +20) dre ů 6202 tsara² + Ire- 20) dre 2 -272 +143-20) de C .

- then Soy bonbs s = +8+ PŁ- = tot sit ose- - Osz = 3 DT82- 917 99)- SEIt öst- = (ob-ort ;-)-6001 – sti + -) = (ove-ac29e+ęcer#2) -(510x=($){*°**) = lleot-zvoltx 3) - 1+1 「 て、 LO7 Tiet - 222