Use R to identify the elements as well as their index(s) of the sequence {2^1,2^2,...,2^15} that exceed the corresponding elements of the sequence {1^3,2^3,...,15^3}. Please use Rstudio
CODE:
seqA <-2^(1:15)
seqB <-(1:15)^3
for (i in seq(1, 15, by=1)) {
if(seqA[i]>seqB[i]){
cat("index : ",i,"\tElement : ",seqA[i],"\n")
}
}
SCREENSHOT:
SAMPLE OUTPUT:
***Please upvote if it helps and feel free to comment if you have any query
Use R to identify the elements as well as their index(s) of the sequence {2^1,2^2,...,2^15} that...
do (b) please 2. (15 marks) Consider the abstract datatype SEQ whose objects are sequences of elements and which supports two operations . PREPEND(x, S), which inserts element r at the beginning of the sequence S and . ACCESS(S, i), which returns the ith element in the sequence Suppose that we represent S by a singly linked list. Then PREPEND(, S) takes 1 step and ACCESS(S, i) takes i steps, provided S has at least i elements Suppose that S...
this is using MATLAB 2. Fibonacci sequence: A Fibonacci sequence is composed of elements created by adding the two previous elements. The simplest Fibonacci sequence starts with 1,1 and proceeds as follows: 1, 1, 2, 3, 5, 8, 13, . However, a Fibonacci sequence can be created with any two starting numbers. Create a MATLAB function called FL_fib_seq' (where F and L are your first and last initials) that creates a Fibonacci sequence. There should be three inputs. The first...
An array A[1,2,... ,n is unimodal if its consists of an increasing sequence followed by sequence a decreasing sequence. More precisely, there exists an index k є {1,2,… ,n} such that there exists an indes . AlE]< Ali1 for all 1 i< k, and Ai]Ali 1 for all k< i< n A1,2,..,n] in O(logn) time the loop invariant (s) that your algorithm maintains and show why they lead to the correctness Give an algorithm to compute the maximum element of...
The Fibonacci sequence is the sequence of numbers: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, … The next number is found by adding up the two numbers before it. For example, the 2 is found by adding the two numbers before it (1+1). The 3 is found by adding the two numbers before it (1+2). The 5 is found by adding the two numbers before it (2+3), and so on! Each number in the sequence is called...
one sequence contains E-L-K-D-L-S-K-S and the other contains L-R-K-L-E-R-S-L. please draw helical wheels and identify the interactions between the 2 wheels. What secondary structure does this form?
f a as a sequence of adjacent array elements such that each value in the run array was of size 10 9. We define a "run" of elements o (except for the first) is one greater than the previous and looked like: value. For example, say the 3 2 16 9 7 8 9 2 a: position 0 3 We have three runs in this array: (1) between 9,10,1, 12) and, (3) between positions 7 and 8, (15, 16) positions...
Let T: R3 - R be a linear transformation such that T(1,1,1)= (2,0,-1) T(0,-1,2)=(-3,2,-1) T(1,0,1)= (1,1,0) Find T (2,-1,1). a) (10,0,2) b) (3,-2-1) c)(2,2,2) d) (-3,-2, -3)
Propose synthetic mechanisms for the 3 reactions below. НО (R)-1-phenyl-1,2-ethanediol (S)-1-phenyl-1,2-ethanediol
Let S be a sequence of n distinct integers stored in an array as array elements S[1], S[2], · · · , S[n]. Use the technique of dynamic programming to find the length of a longest ascending subsequence of entries in S. For example, if the entries of S are 11, 17, 5, 8, 6, 4, 7, 12, 3, then one longest ascending subsequence is 5, 6, 7, 12. Specifically: (a) define a proper function and find the recurrence for...
Synthesis Based Experiment 1: Free Radical Bromination of 1,2-Diphenylethane 1. If the R,R and S,S enantiomers of 1,2-dibromo-1,2-diphenylethane have an observed melting point range of 113 -114'C and the meso 1,2-dibromo-1,2-diphenylethane has an observed melting point range of 236-237 C, which stereoisomer did you isolate? TLC 2. All three of these dibromo stereoisomers were produced in this reaction but you only isolated one of them. Explain this result taking into account the large differences in the three stereoisomers melting point...