Question

May you please help with solving this organic chemistry question about Epoxides?

pointus nucleophie. for Epoxide, A draw an arrow at the carbon atom attacked by the B.) Draw the major product 6) Identify the talesphale. major product Nucloophop CH 3 CH 2 OH H2SO4 (dilute) 10 CH3 CH ₂ OH CH CHZONA

Answer 1

The carbon in the epoxide is very reactive electrophile due to ring strain which is released when ring opens upon. nucleophilic attack. нс" } } életerophilic CH In prosence of acid Chansey) 74 the ring opening reaction occars by SN, 4 Sar. carbon. reaction? First oxygen is protonated & forma good leaving group. Then carbon - Oxygen bond stars to break. The positive charge which is built up with more substituted carbon is more stable. V -o-H # Soy CH₂CH=0-t Ah-0-4 ot duet here, unlike sal reaction, the nucleophile (Chaetholt) attack the electrophilic carbocation intermediate before complete carbocation in ofer mediate is formed nucleophile the CH OH

(ii) In absence of acid but presence of strong nucleophile Naoch, the reaction. undertoer like sNr reaction. Here nucleophile attoets less substituted carbon of epoxide. 0:- 120.-ch-cky a Ba, ht OCH3 Na ocity Us substituted carbon Ob 4 octo (orajor product) Nucleophile: Chelt o