Question

Suppose als and bls and ged(a,b)=1. Prove that abls

Answer 1

we have Suppere als 4 bls & g. c.d. (a, b) = 1, then to prove that able Now Now als slea ble a.bls.b a bla. s - is i ) Alio g.e.d. (a, b) = 1 - 7 ney eit. ant by = 1 multiply both side by s, we get a sn + bey= s Now ablas then ablasia & ab/bs then abl bs.y isho as a s. a + b sty i.e. able & abls.

Suppare f. 2 - {0, 13 defind as £18)= so l if if & is add so is even If we take si4 s both add , then daithe is even. de, f 18, +22)=1 (18.)=0 & f1&2)=0 a fls.). E k) = 0 f(sitre) & flei). f1&2) when sit die both are add. is not true for So f18,th) = every pair af f(8,). E122) sit de.

If you have any doubt feel free to ask in the comment section.