The zero order reaction 2N2O→2N2+O2 has the rate constant 5.8×10−4 mol/L/s. If the concentration of N2O at t=10 seconds is 0.152 mol/L, what was the initial concentration of N2O?
we have:
[N2O] = 0.152 M
t = 10.0 s
k = 5.8*10^-4 M/s
use integrated rate law for 0 order reaction
[N2O] = [N2O]o - k*t
0.152 = [N2O]o - 5.8*10^-4*10
[N2O]o = 0.158 M
Answer: 0.158 M
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