Question

ontrol Structures e air with an initial vel tial velocity tion with the on the initia distance (d) from the in TRAJECTORY OF A STONE Consider the trajectory of a stone that is hurled into the air with at an angle to the horizontal of 8 radians. Neglecting drag due to atmosphere, the following equations describe the stone's distance spot and the height (b) of the stone at time t: d=v. t.cos e b = v•l• sin 0 - 1/2 g. 12 distance and height assuming the initial where g is the acceleration due to gravity (9.8 m/sor 32 ft/s2). 22. Write a program that will generate a table that gives the distance, of the stone for every tenth of a second for 5 seconds, assuming velocity, is 75 ft/s at an angle of 30°. 23. Write a program that will generate a table that gives the distance and of the stone for every tenth of a second for 5 seconds, assuming th velocity in ft/s and the angle in degrees are input by the user. the distance and height onds, assuming the initial

Answer 1

clc
clear all

v = 75; %ft/s
theta = 30; %degree

g = 32; %ft/s^2
t = 0:0.1:5; % seconds

d = v*t*cosd(theta);
b = v*t*sind(theta) - 0.5*g*t.^2;

fprintf('time(s) d(ft) b(ft)\n');
for i=1:length(t)
fprintf('%5.1f %10.3f %10.3f\n',t(i),d(i),b(i))
end

%%output

time(s) d(ft) b(ft)
0.0 0.000 0.000
0.1 6.495 3.590
0.2 12.990 6.860
0.3 19.486 9.810
0.4 25.981 12.440
0.5 32.476 14.750
0.6 38.971 16.740
0.7 45.466 18.410
0.8 51.962 19.760
0.9 58.457 20.790
1.0 64.952 21.500
1.1 71.447 21.890
1.2 77.942 21.960
1.3 84.437 21.710
1.4 90.933 21.140
1.5 97.428 20.250
1.6 103.923 19.040
1.7 110.418 17.510
1.8 116.913 15.660
1.9 123.409 13.490
2.0 129.904 11.000
2.1 136.399 8.190
2.2 142.894 5.060
2.3 149.389 1.610
2.4 155.885 -2.160
2.5 162.380 -6.250
2.6 168.875 -10.660
2.7 175.370 -15.390
2.8 181.865 -20.440
2.9 188.361 -25.810
3.0 194.856 -31.500
3.1 201.351 -37.510
3.2 207.846 -43.840
3.3 214.341 -50.490
3.4 220.836 -57.460
3.5 227.332 -64.750
3.6 233.827 -72.360
3.7 240.322 -80.290
3.8 246.817 -88.540
3.9 253.312 -97.110
4.0 259.808 -106.000
4.1 266.303 -115.210
4.2 272.798 -124.740
4.3 279.293 -134.590
4.4 285.788 -144.760
4.5 292.284 -155.250
4.6 298.779 -166.060
4.7 305.274 -177.190
4.8 311.769 -188.640
4.9 318.264 -200.410
5.0 324.760 -212.500
>>

%%(2)

clc
clear all

v = input('Initial velocity(ft/s) :');
theta =input('theta(degree) :');

g = 32; %ft/s^2
t = 0:0.1:5; % seconds

d = v*t*cosd(theta);
b = v*t*sind(theta) - 0.5*g*t.^2;

fprintf('time(s) d(ft) b(ft)\n');
for i=1:length(t)
fprintf('%5.1f %10.3f %10.3f\n',t(i),d(i),b(i))
end

Initial velocity(ft/s) :100
theta(degree) :35
time(s) d(ft) b(ft)
0.0 0.000 0.000
0.1 8.192 5.576
0.2 16.383 10.832
0.3 24.575 15.767
0.4 32.766 20.383
0.5 40.958 24.679
0.6 49.149 28.655
0.7 57.341 32.310
0.8 65.532 35.646
0.9 73.724 38.662
1.0 81.915 41.358
1.1 90.107 43.733
1.2 98.298 45.789
1.3 106.490 47.525
1.4 114.681 48.941
1.5 122.873 50.036
1.6 131.064 50.812
1.7 139.256 51.268
1.8 147.447 51.404
1.9 155.639 51.220
2.0 163.830 50.715
2.1 172.022 49.891
2.2 180.213 48.747
2.3 188.405 47.283
2.4 196.596 45.498
2.5 204.788 43.394
2.6 212.980 40.970
2.7 221.171 38.226
2.8 229.363 35.161
2.9 237.554 31.777
3.0 245.746 28.073
3.1 253.937 24.049
3.2 262.129 19.704
3.3 270.320 15.040
3.4 278.512 10.056
3.5 286.703 4.752
3.6 294.895 -0.872
3.7 303.086 -6.817
3.8 311.278 -13.081
3.9 319.469 -19.665
4.0 327.661 -26.569
4.1 335.852 -33.794
4.2 344.044 -41.338
4.3 352.235 -49.202
4.4 360.427 -57.386
4.5 368.618 -65.891
4.6 376.810 -74.715
4.7 385.001 -83.859
4.8 393.193 -93.323
4.9 401.385 -103.108
5.0 409.576 -113.212
>>