4. What mass of silver (1) bromide can form when 350 mL of 0.15 M silver...
6. (16 points) Magnesium bromide reacts with silver nitrate to form silver bromide (solid) and magnesium sulfate (aq). A mixture of 50.0 8 of magnesium bromide (MM 184.1 g/mol) and 100 g of silver nitrate (MM- 169.9 g/mol) is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete, Do by ICE Method Type of reaction Double displacement 2015 MgBra (5) + 2 AgNO,(aq) > Mg(NO)2(aq)...
6. (16 points) Magnesium bromide reacts with silver nitrate to form silver bromide (solid) and magnesium sulfate (aq). A mixture of 50.0 g of magnesium bromide (MM - 184.1 g/mol) and 100 g of silver nitrate (MM- 169.9 g/mol) is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete, Do by ICE Method Type of reactionDouble displacement 2115 MgBra (s) 2 AgNO (aq) > Mg(NO3)2(aq)...
Question 71. If 25.0 mL of 0.150 M aluminum bromide reacts with 15.0 mL of 0.200 M silver nitrate, what mass of silver bromide is produced? AgBr ()+ AI(NO3)3 (aq) AIBr3 (aq)+AgNO3 (aq) a) 2.11 x 104 g b) 2.11 g c) 5.63 x 104 g d) 0.563 g e) none of the above Question 72 What is the molarity of aluminum ions in the above question before the reaction has taken place? a) 0.150 M A13 b) 0.350 M...
Given that 50.0 mL of 0.100 M magnesium bromide reacts with 13.9 mL of silver nitrate solution according to the unbalanced equation MgBr2 + AgNO3 = AgBr + Mg(NO3)2 (a) What is the molarity of the AgNO3 solution? (b) What is the mass of AgBr precipitate?
When 25.0 mL of a 2.7010-4 M silver nitrate solution is combined with 18.0 mL of a 7.80x10-5 M sodium bromide solution does a precipitate form? (yes or no) For these conditions the Reaction Quotient, Q, is equal to
31. When 75.00 mL of 0.1500 M Silver nitrate and 75.0 mL of 0.150 M HCl are mixed in a constant-pressure calorimeter, the temperature of the mixture increases from 22.00 °C to 24.11 °C. The temperature increase is caused by the following reaction: AgNO3(aq) + HCl(aq) AgCl(s) + HNO3(aq) Calculate AH for this reaction in silver nitrate, assuming that the combined solution has a mass of 150.0 g and a specific heat of 4.184 J/g °C. A. -128.00K) B. 128.00...
31. When 75.00 mL of 0.1500 M Silver nitrate and 75.0 mL of 0.150 M HC) are mixed in a constant-pressure calorimeter, the temperature of the mixture increases from 22.00 °C to 24.11 °C. The temperature increase is caused by the following reaction: AgNO3(aq) + HCl(aq) → AgCl(s) + HNO3(aq) Calculate AH for this reaction in silver nitrate, assuming that the combined solution has a mass of 150.0 g and a specific heat of 4.184 J/g °C. A. -128.00KJ B....
How
many grams of AgNO3 are required to make 770.0 mL of a 0.15 M
solution?
How many grams of AgNO3 are required to make 770.0 mL of a 0.15 M solution? The molar mass of silver nitrate is 169.9 g/mol. One approach is to solve the molarity relationship (M- n/N) for moles. o a 19.6g b. 6.82 g O5.10 g o d. 1.95 g O e. None of the above
Question 1 According to the following reaction, what mass of silver nitrate would be required to react with 0.500 grams of potassium chloride? AgNO3 (aq) + KCl (aq) --> AgCl (s) + KNO3 (aq) options 2.68 g 0.500 g 85.0 g 170 g 1.14 g Question 2 Consider the reaction: Na2CO3 (aq)+ 2 HCl (aq) --> 2 NaCl (aq) + CO2 (g) + H2O (l) If 43.41 g of sodium carbonate react completely, how many grams of HCl will be...
Suppose 0.153 g of iron(II) bromide is dissolved in 50. mL of a 10.0 m M aqueous solution of silver nitrate. Calculate the final molarity of bromide anion in the solution. You can assume the volume of the solution doesn't change when the iron(II) bromide is dissolved in it. Round your answer to 2 significant digits. ПМ x s ?