X-rays of wavelength 0.0983nm are directed at an unknown crystal. The second diffraction maximum is recorded...
X-rays of wavelength 0.0983nm are directed at an unknown crystal. The second diffraction maximum is recorded when the X-rays are directed at an angle of 23.7 degrees relative to the crystal surface.
What is the spacing between crystal planes?
Homework Answers
This is just basic Bragg diffraction
. Use the standard equation: n x lambda = 2d x sin(theta)
For the 2nd strong max, n = 2, lambda = 0.0983nm = 0.0983x10^-9m, theta equals 23.7 deg
d = 0.24nm
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