Question

X-rays with a wavelength of 0.0711 nm create a diffraction pattern when they pass through a...

X-rays with a wavelength of 0.0711 nm create a diffraction pattern when they pass through a protein crystal.

Part A

If the angular spacing between adjacent bright spots (m=0 and m=1) in the diffraction pattern is 31.9 ∘, what is the average spacing between atoms in the crystal?

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Answer #1

Solution:

Given:

Wavelength () = 0.0711 nm = 0.0711 x 10-9 m

Angular separation () = 31.9o

Let, the average spacing between atoms in the crystals be : d.

for the angular spacing between adjacent bright spot : d sin =

d = / sin = (0.0711 x 10-9 m) / sin(31.9) = 1.345 x 10-10 m

Therefore: the angular spacing between adjacent bright spot is 1.345 x 10-10 m.

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