X-rays with a wavelength of 0.0711 nm create a diffraction pattern when they pass through a protein crystal.
Part A
If the angular spacing between adjacent bright spots (m=0 and m=1) in the diffraction pattern is 31.9 ∘, what is the average spacing between atoms in the crystal?
Solution:
Given:
Wavelength () = 0.0711 nm = 0.0711 x 10-9 m
Angular separation () = 31.9o
Let, the average spacing between atoms in the crystals be : d.
for the angular spacing between adjacent bright spot : d sin =
d = / sin = (0.0711 x 10-9 m) / sin(31.9) = 1.345 x 10-10 m
Therefore: the angular spacing between adjacent bright spot is 1.345 x 10-10 m.
X-rays with a wavelength of 0.0711 nm create a diffraction pattern when they pass through a...
X-rays with a wavelength of 0.0711 nm create a diffraction pattern when they pass through a protein crystal Part A If the angular spacing between adjacent bright spots ( mand m-1) in the diffraction pattem is 329, what is the average spacing between atoms in the crystal HA ? Value Units Sum Restas
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