Here relation R is defined over Z.
in Z x Z, for all oder pairs (p, q) where p,q belongs to Z, if p = q then (p, q) is not in relation R.
a) aRb is in relation R if and only if a != b .
b) R2 is defined by a R2 b if and only if there is some x in Z such that a R x and x R b both are ture.
now according to relation R , if a R x is true then x != a .
if x R b is true then x != b.
Now, we can say that there has to be some order pair (x, a) in R such that x R a is true , as x != a.
so in other words : R can have aRx and xRa both.
In that case R2 will be defined on aRa too.
Hence R2 will have all order pairs of elements a and b from Z even when a = b.
so we can say that R2 = Z x Z.
If you have any doubts, you can ask in comment section.
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