Question

Given: The plate is subjected to the couples and forces shown (P = 0 N). The couple @ F is 42 N.m CCw and the couple @H is 40 N m CCW Find: The plate is to be held in place by one rivet that can resist a force but not a couple. Determine the location of the rivet hole along the line that passes through FG relative to the top of the plate (ED) such that the plate would not rotate. Retain three significant digits in your final answers. For your diagram, carefully and neatly sketch the plate (to scale but no dimensions necessary) and the resultant force at the rivet location described above. Write the magnitude and the angle relative to FG next to the force Hint This is a force-only equivalent system problem 120 N 240 mm 200 N 15 70° 50 mm 42 N m 80 N 520 mm 40 N m 180 mm 50 mm 50 mm 640 mm

Answer 1

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Equivalent force: F-n = (200 cos 15 degree - 120 cos 70 degree) = 152 Kn F_y = 200 sin 15 degree + 80+ 120 sin 706 degree = 244.53 N let we place rivet at I so, balance moment about F F_n times d = 42 + 40 + (200 sin 15 times 0.05) - (200 cos 15 times 0.05)+ (120 cos 70 times 0.05) - (120 sin 70 times 0.19) - (80 times 0.59) d = 8.356/152.14 = 0.055m = 55mmm so distance per plate ED(= d + 50) mm = (55 + 50)mm = 105 mm