Question

H Times New Rom - 10-AAA BTWA EEEE ABCD AaBbcc Normal 1 No Spac. Aalbot Heading I - Fone Style Reminder placeholder values are 128-64-32 - 168_4-2-1 Convert the following binary subnet masks into a dotted decimal version of the Subnet Mask 1st Octet 2-Octet 3. Octet 4-Octet Decimal Subnet Mask hosts/network 11111111 11111111 11111111 11111100 255.255.255.252

How do you determine the # hosts / network. as stated in the last column to the far right of the pick?

Answer 1

Subnet Mask : 11111111.11111111.11111111.11111100

Equivalent Decimal Subnet Mask: 255.255.255.252

To find Network Address, We do logical and of Subnet Mask and IP address.

In the 32 bit subnet mask, first 30 bits are 1's . This means first 30 bits are reserved for network address and last two bits are for host address. Using 2 bits, we can accommodate 4 hosts(2^2). But in every network first address and last address are reserved for network identification and broadcast. So we cant use those two addresses for hosts. So from 4 hosts, we substract 2 . So we are remained with only 2 hosts.