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A jet of water having a cross-sectional area of 4 in2 strikes the fixed blade with a speed of 25 ft/s. Determine the horizont

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Answer #1

V sínso Area - 4in? vewerty a 25ffls Nw = 62.4 66/6+3 Flow rate, d= A reax Velocity Area = Te ay . Qe te dy x 25 = 0.69464?lForce = change in momentum Fx = m ( Vfm Vide = 1-3458 (-16.06-25) Ex = = 55.25 lb Fy = m ( VF - Vila - 13458 ( 19.15-0) fp =

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