Question

Please be careful of power of tenth and sign error.

==== Before After

A circuit is made of an ideal battery and a parallel plate capacitor. The capacitor was charged without any dielectric between the plates, as shown on the left. Without disconnecting the circuit,

1. A dielectric material with dielectric constant K=2.4 was inserted into the capacitor. voltage across the capacitor shown on the left was 9.0 V and the charge on the capacitor was 0.24 coulombs. After the dielectric was inserted what was the voltage(in volts) ACROSS the capacitors?

2. A dielectric material with dielectric constant K=3.2 was inserted into the capacitor. voltage across the capacitor shown on the left was 9.0 V and the charge on the capacitor was 0.10 coulombs. After the dielectric was inserted what was the charge(in coulombs) ON the capacitors?

A circuit is made of an ideal battery and a parallel plate capacitor. There is no battery.The capacitor was charged without any dielectric between the plates, as shown on the left.

3.A dielectric material with dielectric constant K=5.3 was inserted into the capacitor. voltage across the capacitor shown on the left was 9.0 V and the charge on the capacitor was 0.26 coulombs. After the dielectric was inserted what was the voltage(in volts) across the capacitors?

4.A dielectric material with dielectric constant K=5.0 was inserted into the capacitor. voltage across the capacitor shown on the left was 9.0 V and the charge on the capacitor was 0.22 coulombs. After the dielectric was inserted what was the charge(in coulombs) ON the capacitors?

Answer 1

and charge (1) Nottage across the capacitor before insertion of didectric, V=qu O = 0.240 y is After insertion, boffeey Congected, across Capacitor Constant- Voltage after insestion; so voltage a remains (2) K = 3.2 O= 0.1c 0.1 9 V V=9u Capac acitance, e- After dielectric insertion; Capacitance (CV) = KC = 3.2.XD!! charge on the capacitor, caffer dielectric insertion O'= CV 9 = 3.240.1 x 9 0.32c 9

(3) V=9v V=9v, a = 0.2be, K=5.3 Afte dielectric in section, decreases Voltage acroes V = V 5.3. capacitor V = 1.69811v (4) Vaqu, a = 0.22c, K=5 After insertion og dilectric there no effect on charge. so charge า นาง Constant. O = 0.220 ie
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