The confidence Interval for difference in proportions is D Zc*SE
D = 0.1, Zc = 1.96 and SE = 0.0604
The lower Limit = 0.1 - (1.96*0.0604) = -0.018
The upper Limit = 0.1 + (1.96*0.0604) = 0.218
The 4th Option (-0.018,0.218)
Question 2 (2 points) Random samples from two age groups of brides (200 brides under 18...
An insurance company selected samples of clients under 18 years of age and over 18 and recorded the number of accidents they had in the previous year. The results are shown below. Under Age of 18 ni = 500 Number of accidents = 180 Over Age of 18 n2 = 600 Number of accidents = 150 We are interested in determining if the accident proportions differ between the two age groups. Refer to Exhibit 11-7. The p-value is a. 0.3...
An insurance company selected samples of clients under 18 years of age and over 18 and recorded the number of accidents they had in the previous year. The results are shown below. Under Age of 18 Over Age of 18 n1 = 500 n2 = 600 Number of accidents = 180 Number of accidents = 150 We are interested in determining if the accident proportions differ between the two age groups. The p-value is:
Question 9 An insurance company selected samples of clients under 18 years of age and over 18 and recorded the number of accidents they had in the previous year. The results are shown below. Under Age of 18 ni = 500 Number of accidents = 180 SO-3 Over Age of 18 n2 = 600 Number of accidents = 150-36 Soo-.36 ISO - 3 180 360 .64 u 600 We are interested in determining if the accident proportions differ between the...
Question 5 2 pts Country Financial, a financial services company, uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time (USA Today, April 4, 2012). In February of 2012, a sample of 1000 adults showed 410 indicating that their financial security was more than fair. In February of 2010, a sample of 900 adults showed 315 indicating that their financial security was more than fair What is a 95% confidence interval estimate...
Vy > A random sample of 40 adults with no children under the age of 18 years results in a mandaly leisure time of 5.69 hours, with a standard deviation of 2.32 hours. A random sample of 40 adults with children under the age of 18 results in a mean dailyleisure time of 4.25 hours, with a standard deviation of 1.62 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between aduts with no...
(2 points) Two random samples are taken, one from among first year students and the other from among fourth-year students at a public university. Both samples are asked if they favor modifying the student Honor Code A summary of the sample sizes a group answering yes" are given below: nd number of each First-Years (Pop. 1): ni - 88, xi -42 Fourth-Years (Pop. 2): n2 -83, x2 4 Is there evidence, at an a 0.01 level of significance, to conclude...
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.16 hours, with a standard deviation of 2.42 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.16 hours, with a standard deviation of 1.58 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between adults with no...
A random sample of 40 adults with no children under the age of 18 years results in a mean daily leisure time of 5.57 hours, with a standard deviation of 241 hours. A random sample of 40 adults with children under the age of 18 results in a meandaly leisure time of 424 hours, with a standard deviation of 1.73 hours. Construct and interpreta 90% confidence interval for the mean difference in leisure time between adults with no children and...
A random sample of 40 adults with no children under the age of 18 years resuts in a mean daily leisure time of 5.74 hours, with a standard deviation of 2.32 hours. A random sample of 40 adults with children under the age of 18 results in a mean daily leisure time of 4.11 hours, with a standard deviation of 1.73 hours. Construct and interpret a 90% confidence interval for the mean difference in leisure time between adults with no...
4. Where people turn for news is different for various age groups. (Data extracted from "Cellphone Users Who Access News on Their Phones," USA Today, March 1, 2010, p. 1 A.) A study was conducted on the use of cellphones for accessing news. The study reported that 47% of users under age 50 and 15% of users age 50 and over accessed news on their cellphones. Suppose that the survey consisted of 1,000 users under age 50, of whom 470...