A 20.0 mL sample of 0.150M ethylamine is titrated with 0.0981 M HCl. What is the pH after the addition of 5.0 mL of HCI? For ethylamine, pkb =3.25.
A 20.0 mL sample of 0.150M ethylamine is titrated with 0.0981 M HCl. What is the...
A 20.0 mL sample of 0.150 M ethylamine is titrated with 0.0878 M HCl. Part A What is the pH after the addition of 5.0 mL of HCl? For ethylamine, pKb = 3.25. 0 11.52 O 9.98 04.02 O 10.75 Submit Request Answer
2. A 35.00-ml sample of a 0.0870 M solution of ethylamine, C2H5NH2 (Kb = 5.6 x 10), is titrated with 0.150 M HCI. (a) What is the equivalence volume of HCI? (b) Calculate the pH of the solution: (1) prior to the start of the titration. (ii) after addition of 10.15 mL of the 0.150 M HCI. (iii) after addition of 14.50 mL of the 0.150 M HCI. (iv) after addition of 6.00 mL of the HCl beyond the equivalence...
A 20.0-mL sample of 1.50 M NH3 is titrated with 0.15 M HCl. What is the pH of the solution after 12.00 mL of acid have been added to ammonia? Kb for NH3 = 1.8 × 10–5
A 10.00 mL sample of 0.300 M NH3 is titrated with 0.100 M HCl (aq). what is the initial pH? Calculate the pH after the addition of 10.0, 20.0, 30.0 and 40.0 mL of HCl. The Kb for NH3 is 1.8 x 10^-5
A 20.0-mL sample of 1.50 M NH3 is titrated with 0.15 M HCl. What is the pH of the solution after 12.00 mL of acid have been added to ammonia? Kb for NH3 = 1.8 × 10–5 5.93 9.30 8.06 9.07 10.45
A 25.0 mL sample of a 0.2800 M solution of aqueous trimethylamine is titrated with a 0.3500 M solution of HCl. Calculate the pH of the solution after 10.0, 20.0, and 30.0 mL of acid have been added; pKb of (CH3)3N = 4.19 at 25°C. pH after 20.0 mL of acid have been added =
A 24.1 mL sample of 0.215 M ethylamine, C2H5NH2, is titrated with 0.363 M nitric acid The pH before the addition of any nitric acid is required Use the Tables link in the References for any equilibrium constants that are
A 24.1 mL sample of 0.215 M ethylamine, C2H5NH2, is titrated with 0.363 M nitric acid The pH before the addition of any nitric acid is required Use the Tables link in the References for any equilibrium constants that are
1. A 23.6 mL sample of 0.391 M ethylamine, C2H5NH2, is titrated with 0.315 M nitric acid. At the equivalence point, the pH is . Ethylamine Kb = 4.3X10-4 Nitrous acid Ka1 = 4.5x10-4 2. A 29.1 mL sample of 0.336 M ethylamine, C2H5NH2, is titrated with 0.276 M hydrochloric acid. After adding 52.4 mL of hydrochloric acid, the pH is . hydrochloric acid Ka1 = 3.5x10-8 Ethylamine Kb = 4.3X10-4
A 25.0 mL sample of 0.203 M ethylamine, C2H^NH2, is titrated with 0.225 M nitric acid. Before the addition of any nitric acid, the pH is (2) After adding 8.62 mL of nitric acid, the pH is (3) At the titration midpoint, the pH is (4) At the equivalence point, the pH is (5) After adding 35.4 mL of nitric acid, the pH is Use the Tables link on the toolbar for any equilibrium constants that are required. Not submitted...
A 50.0 mL solution of 0.137 M KOH is titrated with 0.274 M HCl. Calculate the pH of the solution after the addition of each of the given amounts of HCI. 0.00 mL pH = 5.00 mL pH = 12.5 mL pH = 20.0 mL pH = 24.0 mL pH = 25.0 mL pH= 26.0 mL pH = 29.0 mL pH =