Given the following sample information, test the hypothesis that the treatment means are equal at the 0.10 significance level:
Treatment 1 | Treatment 2 |
Treatment 3 |
3 | 9 | 6 |
2 | 6 | 3 |
5 | 5 | 5 |
1 | 6 | 5 |
3 | 8 | 5 |
1 | 5 | 4 |
4 | 1 | |
7 | 5 | |
6 | ||
4 |
1. What is the decision rule? (Round the final answer to 2 decimal places.)
Reject H0 if F > _______ 1.29 is incorrect.
Please explain how you got your answer. I am very new to statistics so the clearer the better.
Answer
we need to use ANOVA to test for the mean different in this case
ANOVA has two degree of freedoms
df1 (degree of freedom of numerator)= number of categories - 1
= 3 - 1 ........because we have 3 treatments, so 3 categories
= 2
and
df2 (degree of freedom of denominator)=total data values - number of categories
= 24-3
= 21
using excel function F.INV.RT(alpha,df1,df2)
setting alpha = 0.10, df1 = 2 and df2 = 21
we get
F critical = F.INV.RT(0.10,2,21)
= 2.57
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