QUESTION 1 11 poin Given the following endothermic reaction, predict which way the reaction will shift...
QUESTION 1 The following reaction is endothermic. Which change will shift the equilibrium to the right? 2 503(9) = 2 SO2(g) + O2(9) removing SO3 adding SO2 none of the other answers are correct decreasing the volume (increasing the pressure) decreasing the temperature w
Which of the following would increase the yield of the products of the following endothermic reaction? 2H2O(g) + 2Cl2(g) 4HCl(g) + O2(g) ΔH > 0 Question 14 options: 1) Decreasing the temperature of the reaction 2) Adding HCl to the reaction vessel 3) Decreasing the volume of the container 4) Removing Cl2(g) from the reaction vessel 5) Increasing the volume of the container
Worksheet 15 (Gen Chem) Chemical Equilibrium 15. Kp for the following reaction is 0.16 at 25 °C 2 NOBr(g) 2 NO(g) + Br2() The enthalpy change for the reaction at standard conditions is +16.1 kJ. State which way the equilibrium will shift (left, right, or no change) when each of the following changes is made. a. Adding more Bra() b. Removing some NOBr(g) c. Decreasing the temperature d. Increasing the container volume e. Increasing the total pressure by adding an...
For the reaction CHs (a) 3 H2 (a) <=---> CgH,2 (a) + heat Determine which of the following will shift the equilibrium to the left a) adding a catalyst b) decreasing the temperature c) increasing the pressure by decreasing the volume of the container d) increasing the concentration of H2 e) increasing the concentration of CeHe f) decreasing the concentration of C H12 g) more than one correct response h) no correct response O0000O
Which of the following equilibria will shift towards the formation of more products if the reaction at equilibrium is compressed into half its volume? 1. 2N2O(g) + 2N2(g) + O2(g) II. 2CO(g) + O2(g) = 2CO2(g) III. N2(g) + O2(g) + 2NO(g) Both II and III. All three reactions will shift towards the formation of more products. Consider the following reaction at equilibrium. CO2(g) + 2 H2O(l) = CH2(g) + 2O2(g) AH° = +890 kJ Which two of the following...
For the endothermic reaction CaCO3 (s) <-----> CaO (s) + CO2 (g) Le Chtelier's principle predicts that __________ will result in an increase in the number of moles of CO2 at equilibrium. a. increasing the temperature b. decreasing the temperature c. increasing the pressure d. removing some of the CaCO3(s) e. adding more CaCO3 (s)
Consider the reaction, which is exothermic as written, 2H2(g) + X2(8)=2H2X(g). Which of the following changes would result in the production of more H2X(g)? 1. adding H2(8) II. removing H2(8) III. reducing the volume of the container IV. removing X2(8) V. increasing the temperature VI. increasing the volume of the container VII. adding X2(g) VIII. reducing the temperature IX. adding a suitable catalyst
Question 1 Glucose metabolism can be represented by the following chemical reaction: C6H12O6(aq)+6O2(g)6CO2(g)+6H2O(l) H for the reaction is -2837 kJ/mole. Is this reaction endothermic or exothermic? Write an expression for the equilibrium constant for this reaction. Given that the value of the equilibrium constant is very large, would you expect this reaction to be fast or slow? Explain the effect on equilibrium of Increasing temperature Increasing pressure by decreasing the volume Decreasing concentration of oxygen Increasing the concentration of...
Indicate whether the actions below will shift the following reaction: RIGHT, LEFT or NO CHANGE. Heat + NH4CO2NHz(s) <=> 2 NH3(g) + CO2(g) Increasing the quantity of NH4CO2NH2(s) Removing CO2(g) Increasing the volume of the container Increasing the temperature Adding a catalyst right left no change
In the endothermic reaction 2NOBr(g) = 2NO(g) + Br2(g) at equilibrium, which of the following changes will result in an increase in the partial pressure of NOBr? 1. decreasing the partial pressure of Br2 II. increasing the size of the reaction vessel III. lowering the overall temperature of the reaction IV. adding a catalyst V. adding He(g) O A I and II I and II O B lland III O c IV and V IV and V III and V...