Consider these bond energies in kilojoule per mole: Ph–H (473); H–Cl (431); Ph–Cl (407); Cl–Cl (243). Is the reaction at right thermodynamically favorable? Quantitatively justify your answer.
Horxn = Ho of reactants - Ho of products
= 473 - 431
= 42 kJ/mol
here Horxn is positive.
so the reaction at right not thermodynamically favourable
Consider these bond energies in kilojoule per mole: Ph–H (473); H–Cl (431); Ph–Cl (407); Cl–Cl (243)....
show work 9) Given the bond enthalpies Cl-Cl (243), C-CI (339), H-CI (431),C-H (414)all in kJ/mol, estimate AE for the following reaction: CH4(g)+ Cl2(g)-CH3Cl(g)+ HCl(g) A)-1427 k) B) -113 kJ C) -30 kJ D)-356 kJ E) 301 kJ
Use the bond energies below to estimate AH for the following reaction: CH4 (g) + Cl2 (g) - CH3CI (g) + HCl (g) Bond Energies (kJ/mole) single bonds. multiple bonds H C. Cl H. 432. C=O 799 C. 412. 346. C=C.602 O. 459. 358. 142 C=C 835 Cl 431. 328. 242. O=O 494
What is the enthalpy change for the reaction shown below? C2H2 + HCl -> CH2CHCl a. -34 kJ/mole b. -87 kJ/mole c. +34 kJ/mole d. +87 kJ/mole Bond Dissociation Energies Average Single Bond Energies (kJ per mole) H 436414 389 464 569 293 318 339 431 368 297 347 293 351 439 289 264 259 330 276 238 159 201 272 201 243 138 184 368 351 201 159 540 490 285 255 197 176 213 226 360 289 Si...
Given the bond energies (in kJ/mol) of the following bonds: F–F (155), F–Cl (193), and Cl–Cl (243), estimate the molar enthalpy of formation of ClF(g), that is find ∆H for the following reaction ½Cl2(g) + ½F2(g) → ClF(g) A. 209 kJ/mol B. -50. kJ/mol C. –8 kJ/mol D. –209 kJ/mol E. 8 kJ/mol
1. Bond Dissociation Energies and Free Radicals Bond Bond Dissociation Energies (kJ/mol) Bond BDE Bond BDE (kJ/mol) (kJ/mol) H-H 436 CH3-H 439 H-F 570 CH3CH2-H 432 H-CI 432 (CH3CH2 413 BDE Bond (kJ/mol) 10-N 350 0-0 180 F-F O-H 0-C O-F 460 BDE (kJ/mol) | 200 180 159 | H-Br H-I 366 298 404 350 O-C1200 O-Br (CH3)3C-H C-C (sigma) C=C(pi) 210 C1-C1243 Br-Br 193 243 0 -I 220 I-I | 151 A. The enzyme methane monooxygenase catalyzes a remarkably...
1. a. Use the bond energy data provided to calculate AH.. for the following reaction. H-H + Cl-Cl → 2 H-CI Bond Bond Energy H-H 436 kJ/mol Cl-CI 243 kJ/mol H-CI 431 kJ/mol b. Based on your answer to part a, is the reaction an exothermic reaction or an endothermic reaction? Provide a brief explanation to support you choice of answer. An endothermic reaction occurs in a cylinder with initial volume of 1 L. 5 kJ of heat is transferred...
use the bond energies provided in the table to estimate the enthalphy change for the reaction Question 3 Use the bond energies provided in the table to estimate the enthalpy change for the reaction: CH4) + N2Clag) CCl4(g) + N20) + 2H25) 0 -1305 kJ O 1305 kJ O 2107 kJ -501 kJ Question 4 6 pts F. G Н. J к L 4 Enter H- F- N 389 280 201 163 H 435 S 368 343 272 209 F...
The enthalpy change for the following reaction is 81.1 kJ. Using bond energies, estimate the H-Cl bond energy in HCl(g). 2HCl(g) + Br2(g)2HBr(g) + Cl2(g)
Use bond energies to estimate the enthalpy change for the reaction of one mole of CH4 with chlorine gas to give CH3Cl and hydrogen chloride. BEC —H) = 414 kJ/mol BE(C CI) = 326 kJ/mol: BECH - CI) = 432 kJ/mol: BE(CI CI)=243 kJ/mol 1. -101 kJ/mol II. -106 kJ/mol III. +331 kJ/mol IV. +106 kJ/mol V +101 kJ/mol A) I B) II C) III D) IV E) V
According to your textbook, the bond energies for a C=O bond and an O=O bond are 803 and 498 kJ per mole, respectively. Double-check the table to make sure that these values are correct. Based on those values for bond energies, calculate the energy released in this reaction. Your answer should have units of kJ per mole of CO2 formed. C + 02 → CO2