show work 9) Given the bond enthalpies Cl-Cl (243), C-CI (339), H-CI (431),C-H (414)all in kJ/mol,...
Consider these bond energies in kilojoule per mole: Ph–H (473); H–Cl (431); Ph–Cl (407); Cl–Cl (243). Is the reaction at right thermodynamically favorable? Quantitatively justify your answer. (6) Consider these bond energies in kilojoule per mole: Ph-H (473); H-CI (431); Ph-CI (407); Cl-CI (243). Is the reaction at right thermodynamically favorable? Quantitatively justify your answer. +HCl
Calculate ΔH ° in kJ / mol for the reaction: NH3 (g) + Cl2 (g) → NH2Cl + HCl (g) based on the energy of tenons that break and form in the reaction. The bond enthalpies of the following compounds are given: N-H (389), Cl-Cl (243), N-Cl (201), and H-Cl (431) in kJ / mol
Given the bond energies (in kJ/mol) of the following bonds: F–F (155), F–Cl (193), and Cl–Cl (243), estimate the molar enthalpy of formation of ClF(g), that is find ∆H for the following reaction ½Cl2(g) + ½F2(g) → ClF(g) A. 209 kJ/mol B. -50. kJ/mol C. –8 kJ/mol D. –209 kJ/mol E. 8 kJ/mol
C-H bond BDE (kJ/mol) CH3-H 439 C2H:-H 422 (CH3)2 CH-H 414 (CH3)3 C-H 405 Table of Bond Dissociation Enthalpies C-X bond BDE (kJ/mol) X2 and HX bonds BDE (kJ/mol) CH3-C1 351 CI 247 CH-C1 355 НСІ 431 (CH3)2CH-C 355 (CH3)3C-CI 355 CH3 CH3 CH3CHCHCH3 CH3CHCH2CH3 + a Cl2 CI HCI Using the table of bond dissociation energies in the first part of this question: Calculate AH for this reaction. kJ/mol Overall, this reaction is CH3 CH3CHCHCH3 CH3 CH3CHCH2CH3 + b...
For the reaction: H2(g)+C2H4(g)-->C2H6(g) Bond & Bond Enthalpy H-H 436.4 kJ/mole C-H 414 kJ/mol C-C 347 kJ/mol C=C 620 kJ/mol Substance & delta Hf H2 0 C2H4 52.3 C2H6 -84.7 (a) estimate the enthalpy of reaction, using the bond enthalpy values from the table in kJ/mol (b) Calculate the enthalpy of reaction, using standard enthalpies of formation
Using the bond enthalpies in the Average Bond Enthalpies table, determine the approximate enthalpy (in kJ) for each of the following reactions. (Assume the average bond enthalpy of the Cl–F bond is 254 kJ/mol.) (a) Cl2(g) + 3 F2(g) → 2 ClF3(g) (b) H2C=CH2(g) + H2(g) → H3CCH3(g) (c) 2 CH3(C=O)H(g) + 5 O2(g) → 4 CO2(g) + 4 H2O(g) ITITIT Average Bond Enthalpies AH bond (kJ/mol) bond AHond (kJ/mol) bond AH bond (kJ/mol) bond bond AH bond (kJ/mol) С-Н...
Bond Dissociation Energies, Dº298, for X-Y kJ/mol (kcal/mol) X\Y= H F Ci Br I OH NH2 CH3 CH3CH2- CN CH3- CH3CH2 (CH3)2CH- 439 (105) 452 (108) 356 (85) 293 (70) 423 (101) 444 (106) 335 (80) 285 (68) 238 (57) 385 (92) 356 (85) 377 (90) 368 (88) 510 (122) 228 (53) 380 (91) 356 (85) 368 (88) 336 (80) 409 (98) 448 (107) 339 (81) 274 (65) 226 (54) 385 (92) 351(84) 331 (79) 263 (63) 213 (51) 380...
Part A. Given the bond dissociation energies (in kJ/mol) for the following diatomic molecules Cl2 (243), F2 (158), H2 (436), O2 (498), N2 (945) choose the one(s) that could be broken by using blue light (λ=465 nm). Part B. Given the bond energies (in kJ/mol) of the following bonds: F–F (155), F–Cl (193), and Cl–Cl (243), estimate the molar enthalpy of formation of ClF(g), that is find ∆H for the following reaction ½Cl2(g) + ½F2(g) → ClF(g)
Use the bond enthalpies in the table below to determine the enthalpy of reaction in the following questions: Average Bond-Enthalpies- (kJ/mol) Single Bonds -H 41 3 348 293 358 485 N- 391 -H 463 -O 146 F-F 155 N-N 163 N-O 201 272 N-CI 200 N-Br 243 CI-P 253 N-I CI-CI 242 O-CI 203 -I 234 C-C Br-p 237 B-CI 218 Br-Br 193 339 327 S-Cl 253 S-Br 218 S-H 240 259 -X-H 436 567 431 366 299 208 175...
Use the molar bond enthalpy data in the table to estimate the value of AHin for the equation Bond 0-H 0-0 kJ. mol 464 142 351 kJ. mol 890 390 159 CH,() + 4C1,(8) CCI (8) + 4 HCI(g) C-0 The bonding in the molecules is shown. O=0 502 418 C=0 945 730 347 H- Bond CEN N-H N-N N=N N=N F-F CI-CI Br-Br H-H H-F H-CI - Cl C-CI + C CI CCI C-CI 155 HC + H Cl...