Question

1.Calculate the relative abundance of N-ethyl and O-ethyl saccarin obtained. Report your findings as percent N-ethyl and percent O-ethyl. Show your work explicitly

2. In one sentence, state whether your reaction is under thermodynamic control or kinetic control and why you believe the product you obtained is a result of your indicated control. Yield of ethyl saccharin

Product = 0.3642g

Mass of ethyl saccharine = 211g/mol

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Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
Answer #1

The signal at 3.9 ppm corresponding to the CH2 of N-ethylation product and the signal at 4.6 ppm corresponding to the CH2 of O-alkylated product. As you mentioned the integration values of N-alkylated CH2 is 1.57 and O-alkylated CH2 is 0.36 the % of N-alkylated product is (1.57/(1.57+0.36))×100 = (1.57/1.93)×100 = 81% similarly the % of O-alkylated product is (0.36/(1.57+0.36))×100 = (0.36/1.93)×100 = 19%.

Out of 0.3642 g of ethyl saccaride (0.3642×0.19) g = 0.0692 g of O-ethyl saccaride and (0.3642×.81) g = 0.2950 g of N-ethyl saccaride present.

The electronegativity on nitrogen is much less than the electronegativity of Ogygen. So the O-alkylation will be faster but the reaction product destroyed the stability of the saccarine and the ring strain will be higher (less favorable reaction). As a result of it the N-alkylation is the thermodynamically controlled product (TCP) and the O-alkylation is the Kinetically controlled product (KCP). In this case the reaction proceded with thermodynalmic control.

For reaction mechanism see below:

Add a comment
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