4)
Let X denote the blood chloride concentration
Mean, = 104
Standard deviation, = 5
(a) The required probability = P(X < 105)
= P{Z < (105 - 104)/5}
= P(Z < 0.2)
= 0.5793
(b) The required probability = P{|X - | > }
= P{|Z| > 1} = 0.3174
No, this probability does not depend on the values of and
(c) Corresponding to most extreme 0.1% of chloride concentration values, the z values are -3.10 and 3.10 respectively
The lower extreme value of the chloride concentration =
= 88.7
The higher extreme value = = 119.30
5)
Let D denote the diameter of the bearing
Mean, = 0.499 inches
Standard deviation, = 0.002 inches
The required probability = 1 - P(0.496 ≤ D ≤ 0.504)
= 1- P{(0.496 - 0.499)/0.002 ≤ Z ≤ (0.504 - 0.499)/0.002}
= 1 - P(-1.5 ≤ Z ≤ 2.5) = 0.073
Thus, 7.3% of the bearings produced will not be acceptable
• Men's heights are normally distributed with u = 71.2499 inches and o = 14.8530 inches...
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